Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.
Example:
Input:
[1,2,3]
Output:
3
Explanation:
Only three moves are needed (remember each move increments two elements):
[1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
解法1:O(N)
本题巧妙的办法是要想到等价的操作,将n-1个元素都+1等价于将1个元素-1,在选择+1的时候我们都是避开最大的元素,那么-1的时候就要选择最大的元素。那么问题就转化为了将元素全部转化为最小元素,需要多少步,每步减少一个元素的值。
C++12345678910class Solution {public: int minMoves(vector<int>& nums) { int minNum = INT_MAX; int count = 0; for (num : nums) minNum = min(minNum, num); for (num: nums) count += (num - minNum); return count; }};
Java1