Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
解法1:
C++12345678910111213class Solution {public: uint32_t reverseBits(uint32_t n) { int res = 0; for (int i = 0; i < 32; ++i) { res <<= 1; int bit = n & 1; res = res | bit; n >>= 1; } return res; }};
Java1
Follow up
本题的follow up的解法参考这个帖
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